In triangle ABC, Angle A =x° , Angle B =x-40° and Angle C =x+10°. Find Angle C. *
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Answer:
triangle A +B+C = 180° (triangle sum property)
x + x-40 + x+10 =180°
x+x+x -40+10 =180°
3x -30 =180°
3x = 180°+30° (30° sign will change here)
3x= 210°
x= 210/3
x=70°
A=70°
B= X-40° (70-40)
= 30°
C= X+10° (70+80)
=90°
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