in triangle ABC, angle ABC=50degrees and angle ACB=70degrees.AP is the bisector of angle BAC. find angle APB
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Answered by
1
As we know the sum of all the angles of a triangle is 180°
=ABC+ACB+BAC=180°
=50°+70°+BAC=180°
=120°+BAC=180°
=BAC=180°-120°
=BAC=60°
given AP is bisector of BAC
=BAP=1/2 BAC
=60/2
=30°
So;BAP=30°
=ABC+ACB+BAC=180°
=50°+70°+BAC=180°
=120°+BAC=180°
=BAC=180°-120°
=BAC=60°
given AP is bisector of BAC
=BAP=1/2 BAC
=60/2
=30°
So;BAP=30°
mandeepkaur8:
we have to find angle apb not bap
Answered by
2
Step-by-step explanation:
BAP = 30° please mark me as brainlust
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