Question

In triangle ABC,angle ABC=90 AD=DC,AB=12cm and BC=6.5cm. Find the area of triangle ADB​

Answer 1

hi mate here is your answer ,

the area of triangle is

1/2 ×base × hight

so 1/2×6.5×12=39

hope it helps you

Answer 2

Answer:

Hey mate

In ∆ ABC

ANGLE A = 90°

Therefore by Pythagoras theorem

AC² = AB² + BC²

AC² =12²+6.5²

AC² = 144 + 42.25

AC² = 186.25

AC = √ 186.25

AC = 13.6

SINCE AD = DC

THEREFORE AD+ DC = AC

AD+ AD = AC (AD=DC)

2AD = AC

AD = AC÷ 2

AD= 13.6÷ 2

AD = 6.8

THEREFORE AD = DC= 6.8

NOW THE AREA OF ∆ ADB

Now, since BD is the median it divides the ΔABC into two equal parts.

2 × Ar(ΔADB) = Ar(ΔABC)

⇒ 2 × Ar(ΔADB) = 39

⇒ Area of ΔADB = 19.5 cm²

HOPE IT HELPS

PLZ MARK BRAINLIEST