Question

In triangle ABC; angle ABC=90⁰, angle CAB=x⁰, tan x = ¾ and BC = 15 cm. FIND THE MEASURES OF AB AND AC

Answer 1

Step-by-step explanation:

tan x° = 3/4

i.e. perpendicular / base = BC/AB=3/4

Therefore if length of base = 4x, lenght

of perpendicular = 3x

Since, BC²+ AB² = AC² ...{ using

Pythagoras theorem}

(3x)² + (4x)² = AC²

AC²= 9x² + 16x²= 25x²

:. AC = 5x

Now, BC= 15

3x= 15

x = 15

Therefore, AB = 4x

= 4×5

= 20

And, AC = 5x

= 5×5

=25

I hope it's help