in triangle abc , angle abc =90°. AB = 2a+1 and BC = 2a square + 2a . find AC in terms of a
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use pythagoras theorem
ac² =( 2a+1)² + (2a² + 2a)²
ac = √4a² + 1+4a+4a⁴+4a²+8a³
ac = √4a⁴ + 8a³ + 8a² + 4a + 1
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