In triangle ABC; angle ABC=90° and P is a point on AC such that angle PBC=angle PCB. Show that: PA=PB.
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if angle pbc=angle pcb
so pb=pc by isosceles triangle property
if angle pcb =45 degree so angle pab =45 degree
then pa=pb by isosceles triangle property
so pb=pc by isosceles triangle property
if angle pcb =45 degree so angle pab =45 degree
then pa=pb by isosceles triangle property
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