In triangle ABC, angle ADE = angle B, then prove that triangle ADE ~ triangle ABC. Also,if AD=7.6cm , AE=7.2cm, BE=4.2cm and BC=8.4cm, then find DE
Answers
Answered by
2
Hey please give the figure too along with the question. I couldn't understand the question. Please give the figure. Hope you will soon post this question again along with its figure...
Answered by
1
Answer:
Given : AD= 7.6 cm, AE= 7.2 cm, BE= 4.2 cm, BC= 8.4 cm.
In ∆ADE and ∆ABC
∠A = ∠A (COMMON)
∠ADE = ∠ABC (GIVEN)
∆ADE~∆ABC (AA Similarity)
AD/AB = DE /BC
[Ratios of the corresponding sides of the similar triangles are equal]
AD/(AE+BE) = DE/BC
7.6 / (7.2+4.2)= DE/8.4
7.6 /11.4 = DE/8.4
DE= (7.6 × 8.4) /11.4
DE= (7.6×8.4)/11.4
DE = 63.84/11.4= 5.6 cm
Hence, DE= 5.6 cm
Similar questions