In triangle ABC, angle B =100° and AB= AC then angle B = ?
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Don't you think that the question is wrong, already angle B = 100, how we can find angle B
I think it would be angle A or C
So the answer is
AB = AC
angle opposite to equal sides
So Angle A = Angle C
By ASP of triangle
180- 100=80
Let A anb B angle = x
Then 2x =80
X = 40
So angle A and C = 40
I think it would be angle A or C
So the answer is
AB = AC
angle opposite to equal sides
So Angle A = Angle C
By ASP of triangle
180- 100=80
Let A anb B angle = x
Then 2x =80
X = 40
So angle A and C = 40
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