In triangle abc,angle b =105 degree and angle c =50 degree, find angle a
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Answered by
7
Angle a = x
angle b = 105
angle c = 50
a +b +c = 180
x +105 +50 = 180
x + 155 =180
x = 180 - 155
x = 25
angle a =25
hope you like the answer
angle b = 105
angle c = 50
a +b +c = 180
x +105 +50 = 180
x + 155 =180
x = 180 - 155
x = 25
angle a =25
hope you like the answer
Answered by
1
in triangle ABC :
angle A+angle B+angle C=180°
angle A+105°+50°=180°
angle A=180°-105°-50°
angle A=180°-155°
angle A=25°
angle A+angle B+angle C=180°
angle A+105°+50°=180°
angle A=180°-105°-50°
angle A=180°-155°
angle A=25°
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