Math, asked by mohantytruptimayee70, 19 days ago

In triangle ABC,angle B = 45°,angle C= 55°, and the bisector of angle A meets BC at point 'D' .Find angle ADB and angle ADC​

Answers

Answered by anuajmani82
2

Step-by-step explanation:

Correct options are A) and B)

Given ∠B=45,∠C=55

So, ∠A=180°−45°−55°

=80°

From △ABD,40°+45°+∠ADB=180°

⟹∠ADB=95°

From△ADC,40°+55°+∠ADC=180°

⟹∠ADC=85°.

Answered by srivallisarvani98
1

answer:

Angle A= 180°-(55+45)°

=80°

Now,

As AD is bisector

Angle BAD=1/2 Angle A = 40°

In triangle BAD,

Angle ADB

= 180°-(Angle BAD +Angle DBA)

=180°-(40+45)°

=95°

Similarly,

In triangle ACD,

Angle ADC

= 180°-(40+55)°

=85°

answer is 85°

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