in triangle ABC,angle b=60 ,angle C=40 AL perpendicular BC and AD bisects angle A such that l and d lies on side BC find angle LAD
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Angle B = 260 and angle C equals to 40 degree in triangle abc equal to angle 16 degree + 40 degree + angle equals to 180 degree angle equals to 180 degree - 100 degree equals to 18 degree it is the bisector of the angle so angle C is equal to angle dmp no angle C is equals to 18.2 equals to 40 degree now in triangle AC and equals to 19 + 40 degree + angle C is equals to 180 degree angle C A L = to 180 degree minus 30 degree equals to 50 degree angle LED equals to angle C A T - angle C A L = 250 degree minus 40 degree equal to 10 degree so angle and is equals to 10 degrees
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