Question

In triangle abc angle b=90 ,ab=5cm bc=+ac=25cm then find the value of sin a cos a and cosec a

Answer 1

The answer is in the photo plz mark it as brainliest

Answer 2

Answer:

Step-by-step explanation:

First you have to solve for QR and PR.

PR+QR = 25 (given) and PR=25-QR

52 + QR2= PR2 (pythagorean theorem)

Then substitute PR to get this equation =  52 + QR2 = (25-QR)2

Solve for QR

52 + QR2 = 625 - 50QR +QR2                  .........(QR2 cancels out)

52 = 625 - 50 QR

-600 = -50 QR

QR= 12

Solve for PR using original equation.

PR= 13

Now draw the triangle on your paper for help solving the next step...

Sin = opposite/ hypotenuse  Sin(P)= 12/13

Cos= Adjacent/ hypotenuse Cos(P) = 5/13

Tan= opposite/ adjacent  Tan(P) = 12/5