Question

In triangle abc,angle b=90 degree, AB =x+8 BC = x+1 AC =x+15, find the sides of the triangle

Answer 1

Answer:

Step-by-step explanation:

It is an right angles triangle so by pyathagoras theorm

(AB)^2 + (BC)^2=(AC)^2

(x+8)^2 + (x+1)^2=(x+15)^2

x^2+64+16x+x^2+1+2x=x^2+225+30x

x^2-12x-160=0

(x+8) (x-20) =0

x=20, (-8), but sides can't be negative so we'll take x=20

AB=28, BC=21, AC=35