In triangle ABC angle B=90 degree and BD perpendicular to AC , AC=9cm & AB=7cm Find AD
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can you please send the figure
Answered by
1
Answer:
Step-by-step explanation:
Let the length AD=x cm
From triangle ABC, BC=Sqrt(9x9-7x7)=Sqrt32 (By Pythagoras Theorem)
Equating the length of BD in both the triangles ABD and BDC using Pythagoras Theorem, we get
Sq.(BD)=Sq.7-Sq.(x)=32-Sq.(9-x)
or, 49-Sq.(x)=32-(81+Sq.x-18x)=32-81+18x-Sq(x)
or, 49=-49+18x [Sq(x)] term gets cancelled in both sides)
or, 18x=49+49=98
or, x=98/18=49/9=5.44cm
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