Math, asked by Kelsis, 1 year ago

In triangle ABC, angle B=90 degree, if AC =13 cm, BC= 5cm find AB


Kelsis: I need proper working
mohitvishwas: using pythagorian theorm
Kelsis: Even I know the answer. But not sure of the procedure
Kelsis: used Pythagorean theorem but didn't got the answer
mohitvishwas: can you contact me on what's app
mohitvishwas: AC square equal to a b square + b square 13 square equal to 5 square + b square 169 equal to 25 equal to a b 169 - 25 equal to a b square 144 equal to a b square a b equal to root 144 AB equal to 12
Kelsis: I got the answer already... Thanks
mohitvishwas: okk
mohitvishwas: welcome
mohitvishwas: which class do you read

Answers

Answered by MaheswariS
38

\underline{\textsf{Given:}}

\textsf{In triangle ABC,}

\mathsf{\angle\,B=90^\circ,\,AC=13cm,\,BC=5cm}

\underline{\textsf{To find:}}

\textsf{Length of AB}

\underline{\textsf{Solution:}}

\underline{\mathsf{Pythagoras\;theorem:}}

\boxed{\begin{minipage}{8cm}$\\\textsf{In a right angled triangle, square on the hypotenuse}\\\\\textsf{is equal to sum of the squares on the other two sides}\\$\end{minipage}}

\mathsf{In\;\triangle\,ABC,apply\;pythagoras\;theorem}

\mathsf{AC^2=AB^2+BC^2}

\mathsf{13^2=AB^2+5^2}

\mathsf{169-25=AB^2}

\mathsf{144=AB^2}

\mathsf{AB=\sqrt{144}}

\implies\boxed{\mathsf{AB=12\;cm}}

\underline{\textsf{Find more:}}

In triangle ABC angle BAC is 90 degree seg BL and seg CM are medians of triangle ABC. Then prove that 4( BL²+CM²)= 5 BC²

https://brainly.in/question/7952713

BL and CM are medians of ABC right angled at A. Prove that BL2 + CM2 = BC2 + LM2

https://brainly.in/question/29562778

Attachments:
Answered by Aditiran
8

Answer:

5cm is your answer and my answer is correct

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