Question

In triangle ABC angle B = 90 degrees angle A = x degrees angle C = 2x degrees and AB =12 cm. Find BC​

Answer 1

Answer:

i hope answer is 4 × 3^1/2

Step-by-step explanation:

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Answer 2

Answer:

BC = $4\sqrt{3}$

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Step-by-step explanation:

cos(A) = Adj/Hyp

cos(x) = 12/$\sqrt{AB^{2} +BC^{2} }$

sin(C) = Opp/Hyp

sin(2x) = 12/\sqrt{AB^{2} +BC^{2} }

Now, sin(2x) = cos(x)

=> cos(90-2x) = cos(x)

=> 90-2x =x

=> 90 = 3x

=> x=30

Now, tan(x) = BC/AB

=> tan(30) = BC/12

=> $BC= 12/\sqrt[]{3}$

=> BC = $4\sqrt{3}$