Question

In triangle ABC angle B = 90° AB = 2x + 4 BC = x and AC = 2x + 6 Find its sides​

Answer 1

Answer:

for right angle triangle

by Pythagoras theorem

ab^2 + bc^2 = ac^2

(x-3)^2 + (x+4)^2 = (x+6)^2

x^2 -6x +9 + x^2 + 8x + 16 = x^2 + 12x + 36

2x^2 +2x + 25 = x^2 + 12x + 36

x^2 -10x -11 = 0

x = (-b+-√(b^2 -4ac))/2a

x = {-(-10) +- √(100+44)}/2

=(10 +- √144)/2

= (10 +- 12)/2

x=(10+12)/2 or x = (10 -12)/2

x= 22/2 or x = -2/2

x =11 or x = -1

since side cannot be negative

so x = 11

there fore sides of triangle are

x-3 = 11-3=8

x+4=11+4=15

x+6=11+6=17

Hope this answer is help ful for you