Question

in triangle abc, angle b =90° and AC= 8cm. if tan A =2/3, find the lengths of the sides AB and BC.​

Answer 1

Answer:

AB=8*3/$\sqrt{13}$

BC=8*2/$\sqrt{13}$

Step-by-step explanation:

tanA=2/3=BC/AB

cross multiply here,

BC=(2/3)*AC

BC²+AB²=AC²

( (2/3 ) * AB )² +AB²=64

(4/9 )*AB² + AB²=64

(13/9)*AB²=64

AB²=(64*9)/13

AB=√((64*9)/13)

AB=(8 * 3)/√13

So, BC=(2/3) *AB

           =(2/3) * ((8*3)/√13)

            =(8 * 2)/√13

Answer 2

Answer:

Here is the answer for your question in the above attachment

Step-by-step explanation:

I Hope this helps you