Question

In Triangle ABC, Angle B = 90°, AP = 5, PB = 15, PQ = 17 and QC = 7. Find the value of x and y.​

Answer 1

Answer:

∠BDC=90

∘

∠ABC=90

∘

Let ∠BCD=x

∘

Using triangle sum property in △BDC, ∠DBC=90−x

∘

Also ∠ABD=x

∘

Using triangle sum property in △ADB, ∠BAD=90−x

∘

Now considering △BDC and △ADB

∠BDC=∠BDA

∠BCD=∠ABD

∠DBC=∠DAB

So by AAA

△BDC∼△ADB

Hence

CD. BD

BB = AB

5.4

BC

=

3.8

5.7

BC=8.1

Hence BC=8.1cm