Math, asked by thronebone007, 2 months ago

in triangle ABC; angle B= 90°; find: cosAcosC - sinAsinC

Answers

Answered by sara200408

0

Answer:

0

Step-by-step explanation:

cosAcosC - sinAsinC

=cos(A+C)

=cos(π-B)

=[-cosB]

=0

Answered by shobhakumari69519

0

Answer:

0 is the correct answer.

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