in triangle Abc angle B=90° find the value of sinc in triangle Abc where angle B =90°
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We know a+b+c=180
Given =90
So a+b+c = 180
a+c=180-90
a+c=90
Hence 90/2 = 45
Therefore c = 45 ॰
Given =90
So a+b+c = 180
a+c=180-90
a+c=90
Hence 90/2 = 45
Therefore c = 45 ॰
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