In triangle ABC angle B= 90°and AD perpendicular to AC. If DC is 7 cm and AD is 3cm then find the length of BD.
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Answer:
∠ABC=90
o
,BD⊥AC,
BD=8 and AD=4 as in diagram.
Let ∠ACB=x
⇒∠CBD=90−x
⇒∠ABD=x
⇒∠BAD=90−x
⇒ΔABC,ΔADB and ΔBDC are similar
⇒
CD
BD
=
DB
AD
⇒
CD
8
=
8
4
⇒CD=
4
8×8
=16cm.
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