Question

in triangle ABC, angle B = angle C and AD perpendicular to BC. prove that triangle ABD congruent to triangle ACD
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Answer 1

Step-by-step explanation:

In △ADB and △ADC

AB=AC (given)

AD=AD (common side)

∠ADB=∠ADC=90

∘

(AsAD⊥BC)

∴△ADB≅△ADC by RHS property.

Answer 2

Answer:

In △ADB and △ADC

AB=AC  (given)

AD=AD  (common side)

∠ADB=∠ADC=90 (AD perpendicular to BC)

∴△ADB≅△ADC by RHS property.