Question

In triangle abc angle b =angle c and bd=ce.prove that de||bc.

Answer 1

Answer:

hello dear sis/bro

Explanation:

In Triangle ABC we have :-

∠B = ∠C

AC = AB     ( sides opposite to equal angles are equal )

AE + EC = AD + DB

AE + CE = AD + BD

AE + CE = AD + CE ( BD = CE)

AE = AD

Thus we are having :-

AD = AE and BD = CE

Therefore, AD/BD = AE/CE

AD/DB = AE/EC

DE // BC ( By converse of Thales Theorem )

Answer 2

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Here is your solution in the Attachment...

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