In triangle ABC, Angle B=Angle C and ray AX bisects the exterior Angle DAC. If Angle DAX=70, then Angle ACB= *
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Step-by-step explanation:
Angle DAN=70
AN bistects angle DAD
so, angle NAC =DAN=70
DB is a straight line, so angle DAB is 180
=>BAC+70+70=180
=>BAC=180-(70+70)
=180-140
=40
given , angle B=C, Let them be x
so, angle A+B+C=180(sum of angles of a
=>40+x+x=180 triangle is 180)
=> 2x=180-40
=>x=140/2
=70
Hence = 40,70,70.
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