Question

In triangle ABC, angle B=angle C and ray AX bisects the exterior angle DAC. If angle DAX=70°, then what is angle ACB?

Answer 1

Step-by-step explanation:

Angle DAN=70

AN bisects angle DAC

so, angle NAC=DAN=70

DB is a straight line, so angle DAB is 180

so, BAC+NAC+DAN=180

=>BAC+70+70=180

=>BAC=180-(70+70)

=180-140

=40

given, angle B=C,Let them be x

so, angle A+B+C=180(sum of angles of a

=> 40+x+x =180 triangle is 180)

=>2x=180-40

=>x=140/2

=70

ans-40,70,70

hope this helps

Answer 2

Answer:

Angle DAN=70

AN bisects angle DAC

so, angle NAC=DAN=70

DB is a straight line, so angle DAB is 180

so, BAC+NAC+DAN=180

=>BAC+70+70=180

=>BAC=180-(70+70)

=180-140

=40

given, angle B=C,Let them be x

so, angle A+B+C=180(sum of angles of a

=> 40+x+x =180 triangle is 180)

=>2x=180-40  

=>x=140/2

=70

ans-40,70,70

hope this helps

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