in triangle abc angle B equal angle C and BD = CE prove that D E parallel to BC
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i m vipul here
i hope this solution may help u
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proof ....
since angle b=angle c
ab=ac
db=ec(given)
ab/db=ac/ec
subtracting both side by 1
ad/db=ae/ec (by bpt theorem)
hence de parallel to bc....proved
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