Math, asked by DOREN, 2 days ago

in triangle abc angle B equal to 90 degree and AB:AC = 24 : 25 . If BC equals to 14 find the perimeter of triangle ABC​

Answers

Answered by pratyushkatkar111
24

Answer:

112

Step-by-step explanation:

abc is right angled triangle

24:25 = 48 : 50

14^ + 48 ^ =  50^

196+2304=2500

2500=2500

thus sides of triangle 14,48 and 50

perimeter = 50+48+14 = 112

Answered by Anonymous
8

Given:

Angle B = 90°

AB:AC = 24:25

Length of BC = 14

To find:

Find the perimeter of the triangle ABC.

Solution:

It is given the triangle is a right-angled triangle with a right angle at B.

Therefore AB: AC will be equal to cos A.

cos A = 24/25

cos A = 0.96

angle A = 16.26°

Now we will find the angle C using the angle sum property of the triangle.

A + B + C = 180°

C = 180 - ( 90 + 16.26)

C = 73.73°

Now we will find BC using cos C

cos C = BC/AC

cos C = 14/x

0.28 = 14/x

x = 50

therefore AC = 50

Now AB/AC = 24/25

AB = 0.96 x 50

AB = 48

Therefore perimeter of the triangle = AB + BC + AC

= 14 + 50 + 48

= 112 units

Therefore the perimeter of the triangle ABC will be 112 units.

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