Question

In triangle abc angle b equal to 90 degree if ab is equal to 2 cm and ac equal to 3 cm find the value of sin a

Answer 1

Answer:

root5/3

Step-by-step explanation:

by Pythagoras theorem

AB²+BC²=AC²

2²+BC²=3²

BC²=9-4

BC=root5

SIN A=OPP/HYP=root5/3

Answer 2

Answer:

√5/3

Step-by-step explanation:

In ∆ABC , <B=90°

By using Pythagoras theorem

AC²=AB²+BC²

3²=2²+BC²

BC²=3²-2²

BC²=9-4

BC²=5

BC=√5

Sin A = opposite side/Hypotenuse

Sin A = √5/3