Question

in triangle ABC,angle B is 35 °,Angle C=65°and the bisector of angle BAC meets BC in P .arrange AP,BP,CP in decending order



answer please

Answer 1

I hope it is helpful for you

Answer 2

BP > AP > CP

Step-by-step explanation:

Given that,

∠B = 35°

∠C = 65°

By using angle sum property of Δ,

∠A + ∠B + ∠C = 180°

∠A + 35° + 65° = 180°

∠A = 180° - 100° = 80°

∵ ∠BAP = 40° and ∠PAC = 40°(bisector divides in equal halves)

In Δ APB,

∠PAB = 40° > ∠PBA = 35°

PB > AP ....(1)

In Δ ACP,

∠ACP = 60° > ∠CAP = 40°

AP > CP ...(2)

By (1) and (2)

BP > AP > CP

Learn more: Triangles

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