in triangle ABC, angle B is 90. BD is perpendicular to AC. if AD = x, CD = y, BC = a then prove that 1/xy = 1/a^2 + 1/c^2
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sry don't have any idea
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2
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Given ∠ A B C = 90 ∘ , B D
is perpendicular to A C , B D = 8 , and A D = 4
Let
∠ A C B = x ,⇒ ∠ C B D = 90 − x
⇒ ∠ A B D= x ,
⇒ ∠ B A D = 90 − x
⇒ Δ A B C ,Δ A D B , and Δ B DC are similar
⇒ B DC D = A D D B
⇒ 8 C D = 4 8
⇒ C D = 8 ×8 4 = 16
Step-by-step explanation:
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