Question

in triangle abc angle b is equal to 30 degree and ab is equal to 11 cm and BC is equal to 60 CM find AC ​

Answer 1

Answer:

330 cm^2

Step-by-step explanation:

=1/2 base *height

=1/2*11*60

=11*30

=330cm^2

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Answer 2

The length of AC is 51 cm

Step-by-step explanation:

In ΔABC,

∠B = 30°

AB = 11 cm

BC = 60 cm

Using cosine rule:

$c^2=a^2+b^2-2ab\cos C$

$AC^2=BC^2+AB^2-2\cdot BC\cdot AB\cdot \cos30^\circ$

$AC^2=60^2+11^2-2\cdot 60\cdot 11\cdot \cos30^\circ$

$AC^2=2577.85$

$AC=\sqrt{2577.85}\approx 51$

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