Question

In triangle abc angle b is equal to 90 degree and bd is perpendicular to ac find ad if cd =10 and bd=8

Answer 1

Answer:

AD = 6.4

Step-by-step explanation:

in ΔBDC  BD ⊥ CD

=> BC² = BD² + CD²

=> BC² = 8² + 10²

=> BC² = 164

=> BC = 2√41

Δ BDC ≈ ΔADB

as ∠CBD = 90° - ∠C   & ∠A = 90° - ∠C

∠BDC = ∠ADB = 90°

=> BD/CD  = AD/BD = AB/BC

=>  8/10 = AD/8

=> AD = 6.4

Answer 2

Answer:

Answer:

AD = 6.4

Step-by-step explanation:

in ΔBDC  BD ⊥ CD

=> BC² = BD² + CD²

=> BC² = 8² + 10²

=> BC² = 164

=> BC = 2√41

Δ BDC ≈ ΔADB

as ∠CBD = 90° - ∠C   & ∠A = 90° - ∠C

∠BDC = ∠ADB = 90°

=> BD/CD  = AD/BD = AB/BC

=>  8/10 = AD/8

=> AD = 6.4

Step-by-step explanation:

Answer:

AD = 6.4

Step-by-step explanation:

in ΔBDC  BD ⊥ CD

=> BC² = BD² + CD²

=> BC² = 8² + 10²

=> BC² = 164

=> BC = 2√41

Δ BDC ≈ ΔADB

as ∠CBD = 90° - ∠C   & ∠A = 90° - ∠C

∠BDC = ∠ADB = 90°

=> BD/CD  = AD/BD = AB/BC

=>  8/10 = AD/8

=> AD = 6.4