Question

in triangle abc angle b is equal to 90 degree and side BD perpendicular to side AC A-D-C then​

Answer 1

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Let ∠ACB=x,⇒∠CBD=90−x

⇒∠ABD=x,⇒∠BAD=90−x

⇒ΔABC,ΔADB,andΔBDC are similar

⇒BDCD=ADDB⇒8CD=48⇒CD=8×84=16