Question

in triangle abc angle b is equal to 90°, D lies on BC such that BD= CD calculate, (i) tan angle ADB/ tan angle ACB and (ii) tan angle DAB/ tan angle CAB​

Answer 1

Answer:

Explanation:

(i)tan angle ADB = AB/BD

tan angle ACB = AB/BC = AB/(2BD)

tan angle /tan angle  = (AB/BD)/[AB/(2BD)] = 2

(ii)tan angle DAB = BD/AB

tan angle CAB = BC/AB = (2BD)/AB

tan angle /tan angle  = (BD/AB)/[(2BD)/AB] = 1/2

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