Question

in triangle ABC angle b is right angle than find ab=4cm bc=3cm
1.sina cos a
2.sinc.cosc​

Answer 1

Answer:

Step-by-step explanation:

AC^2=BC^2+AB^2

=3^2+4^2

=9+16

=25

squaring both sides

√AC^2=√5^2

square and root get cancelled

so,AC=5

sinA=opp/hyp

=3/5

sinc=4/5

secA=hyp/adj

=5/3

secC=5/4

Step-by-step explanation:

hope it help