in triangle abc, angle bac=90 and angle bca=30, let's prove that ab=1/2 bc
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In ΔABC, ∠BAC = 90° and BCA = 30°; Lets prove that AB = 1/2 BCGiven: ΔABC, ∠BAC = 90° and BCA = 30°....
BC....???
BC = Behan C** Kya.....??
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