Question

in triangle ABC angle bac=90 angle bca=30 prove ab=1/2bc

Answer 1

by taking the concept of congruent triangles

Answer 2

Solution-

The given triangle is a right angle triangle.

Given in the question,

m∠BAC=90° and m∠BCA=30°

We have to prove,

$AB=\frac{1}{2}BC$

From the properties of triangle,

$\sin \theta=\frac{Perpendicular}{Hypotenuse}$

Here,

θ = 30°,

Perpendicular = AB,

Hypotenuse = BC

Putting the values in the formula,

$\Rightarrow \sin 30=\frac{AB}{BC}$

$\Rightarrow \frac{1}{2}=\frac{AB}{BC}$

$\Rightarrow AB=\frac{1}{2}BC$