In triangle ABC angle BAD angle CAD, AB =6cm , AC = 8cm find BD :DC
Answers
Step-by-step explanation:
In △ABC
AD is bisector of ∠A
AC
AB
=
DC
BD
(By basic prop. theorem)
⇒
AC
6
=
6
8
⇒ 8AC=6×6
⇒ AC=
8
6×6
AC=4.5cm
BD : DC = 3 : 4 if in ΔABC ∠BAD = ∠CAD and AB =6cm , AC = 8cm
Given : triangle ABC
∠BAD = ∠CAD
AB = 6 cm
AC = 8 cm
To Find : BD :DC
Solution:
Triangle Angle Bisector Theorem
"A bisector of an angle of a triangle divides the opposite side into two segments that are proportional to the other two sides of the triangle."
∠BAD = ∠CAD
=> AD is bisector of ∠BAC
Using triangle angle bisector theorem :
AB/ AC = BD/ DC
=> 6/8 = BD/DC
=> 3/4 = BD/DC
=> BD : DC = 3 : 4
in triangle ABC angle BAD = angle CAD, AB =6cm , AC = 8cm then BD :DC is 3 : 4
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