Question

in triangle ABC, angle BCA is a right angle, if Q is the midpoint of the side BC, AC=4cm and AQ=5cm,find (AB)2

Answer 1

in triangle,AQC,

AQ^2 = CQ^2 + AC^2

therefore, CQ^2=9

                CQ=3cm

if q is midpoint of BC therefore BC=2*CQ

                                                         =6cm

therefore, In triangle ABC,

By pythagoras theorem, AB^2= AC^2+ BC^2

                                        AB^2 = 52cm^2

or if u want 2*AB=4√13