Question

in triangle ABC, angle C=3 angle B=2(Angle A+ angle B), then find angle A, angle B, angle C

Answer 1

Answer:

By angle sum property

AngleA +angleB+ angleC=180

AngleA +angle B + 3angleB =180

(As angleC= 3 angle B)

Angle A + 4 angle B =180 eq(1)

Now

Angle A + angle B+ angle C =180

Angle A +angle B +2(angleA +angleB)

3angle+ 3angleB = 180 eq(2)

By elimination method

U will get

Angle B = 40

Substitute angle B

Angle A+ 4 angleB =180

Angle A+ 4(40) =180

AngleA= 20

Now angle C =3 angle B

AngleC= 3(40)

AngleC =120

Now u got all the angles

AngleA = 20

AngleB = 40

AngleC = 120

Hope it helps you

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