Question

in triangle ABC ANGLE C =3, THE ANGLE B =2 (THE ANGLE A+ANGLE B), THEN THE SMALLEST ANGLE OF THE TRIANGLE IN DEGREE IS AS

Answer 1

Bro....ur question is not clear...if u can then attach the photo of the question

Answer 2

Let angle A = x
=Angle B = y
=As mentioned in the question angle C = 3 angle B = 3y

Angle C is also given as 2(Angle A + Angle B)

= 2(x+y)

So,

3y = 2(x+y)

y = 2x

So angle C = 3y = 6x

We know that sum of all the 3 angles in a triangle = 180deg

Therefore,

Angle A+ Angle B + Angle C = 180

x+ 2x+ 6x = 180

x = 20

Hence Angle A = 20

Angle B = 40

Angle C = 120