Question

in triangle ABC angle c= 3times angle B=2(angleA +angle B). find all angles?

Answer 1

let the angles be a, b, c
$c = 3b = 2(a + b)$
let b=k
c=3k
and c=2(a+b)
3k=2(a+k)
k=2a
a=k/2
finally
a=k/2,,b=k,,c=3k
so by angle sum prop
a+b+c=180
(k/2)+(k) +(3k) =180
k(1/2 + 1 +3)=180
k(9/2)=180
k=40
so angles are
a=k/2=40/2=20
b=k=40
c=3k=120
mark as brainliest if helped

Answer 2

c=120
a=20
b=40
that's all