Question

in TRIANGLE ABC, ANGLE C = 90°
hypotenuse AB= 3x, BC= 3x/2
Find side AC by pythagoras theorem.
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Answer 1

Answer:

AC= 27x^2/4

Step-by-step explanation:

given,

AB=3x,BC=3x/2

now ,acc. to Pythagoras theorem in right angled triangle ACB

AB^2=BC^2+AC^2

(3x)^2=(3x/2)^2+AC^2

9x^2=9x^2/4+AC^2

9x^2-9x^2/4=AC^2

36x^2-9x^2/4=AC^2

27x^2/4=AC^2

AC=√27x^2/4

therfore AC =3x√3/2