Question

in triangle abc, angle c= 90° then sin (A+B) is
a) 0
b) 1/2
c)1/root2
d) a​

Answer 1

Answer:

This is the answer

solve step by step

Answer 2

Answer:

In triangle ABC , angle C = 90°

Therefore, angle A = 45° and angle B= 45°

Sin(A+B)= Sin (45°+45°)

Sin( A+B) = Sin90°

Sin( A+ B) = 1

Your answer is 1

Hope it will help you......