Question

in triangle ABC,angle C=angle A, angle C-AB=3cm and its perimeter is 15 cm.Find AC

Answer 1

☟☟Here is your answer ☟☟
In ∆ABC
∠A = ∠C [Given]
BC = AB [Angles opposite to equal sides are equal]
Now, perimeter of ∆ABC = 15 cm
AB + BC + AC = 15
AB + AB + AC = 15
2AB + AC = 15 .......(1)
We have,
−AB + AC = 3 .......(2)
Multiply (2) by 2, we get
−2AB + 2AC = 6 .......(3)
Adding (1) and (3), we get
3AC = 21
AC = 7cm

Answer 2

given,✓C=✓A and AB=3cm ,pm=15cm
yes question is solved
as ✓A=✓C
by using the property of isosceles triangle.
✓A=✓C .soAB=BC=3cm
perimeter=AB+BC+AC
15=3+3+AC
AC=15-6=9cm answer
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