Question

In triangle ABC angle C is = 90° angle A = 45° and AB is = 10 cm. using trigonometric ratios find the length of BC.

Answer 1

Answer:

Step-by-step explanation:

1.) In triangle ABC angle A=45

AB=10cm

angleC=90

2.)sin45=p/h

   1/√2=BC/10

  BC=10/√2

Rationalising

5√2 Ans.........

Answer 2

Answer:

 $BC=5\sqrt{2}cm$

Step-by-step explanation:

Given a triangle ABC, ∠C=90°, ∠A=45° and AB=10 cm

We have to find the length of BC.

∠C=90°, ∠A=45°

AB=10cm

$sin45^{\circ}=\frac{BC}{AB}=\frac{BC}{10}$

⇒  $\frac{1}{\sqrt{2}}=\frac{BC}{10}$

⇒   $BC=\frac{10}{\sqrt2}$

Rationalizing, we get

 $BC=5\sqrt{2}cm$