Question

in triangle abc angle equal to 50 degree angle b is equal to 70 degree and bisect of angle C meet ABN D find the angle ADC and bdc in triangle

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

First of all the correct question is "In triangle ABC, angle A is 50degree, angle B is 70 degree and bisector of angle C meets AB in D. find the angles of the triangles ADC and BDC."

-Step by Step explanation:

We know that the sum of all three angles of a triangle is equal to 180°. Therefore, for the given △ABC, we can say that: ∠A + ∠B + ∠C = 180° (Sum of angles of △ABC) 50° + 70° + ∠C = 180°

∠C= 180° –120° ∠C = 60°

∠ACD = ∠BCD =∠C2 (CD bisects ∠C and meets AB in D.)

∠ACD = ∠BCD = 60/2= 30°

Using the same logic for the given △ACD, we can say that:

∠DAC + ∠ACD + ∠ADC = 180°

50° + 30° + ∠ADC = 180° ∠

ADC = 180°– 80°

∠ADC = 100°.

If we use the same logic for the given △BCD, we can say that

∠DBC + ∠BCD + ∠BDC = 180°

70° + 30° + ∠BDC = 180°

∠BDC = 180° – 100°

∠BDC = 80°

Thus, For △ADC: ∠A = 50°, ∠D = 100° ∠C = 30°

△BDC: ∠B = 70°, ∠D = 80° ∠C = 30°

I just hope this helps for you all ........