Math, asked by Shahp2039, 5 months ago

In triangle abc angleA=90 find all the cases in the following sinb,cosc,tanb 1-Ab=Ac=1 (2)Ab=5 Bc=13. 3–Ab=20,Ac=21

Answers

Answered by s1203mansi14894
8

Answer:

With reference to ∠B, we have

Base = AB = 5, Perpendicular = AC = 12 and,

Hypotenuse = BC = 13

∴sinB=

BC

AC

=

13

12

and, tanB=

AB

AC

=

5

12

With reference to ∠C, we have

Base = AC = 12, Perpendicular = AB = 5 and, Hypotenuse = BC = 13

∴cosC=

BC

AC

=

13

12

please mark me brainalist

Answered by ruddrapanchal7
0

Answer:

(1) sin B = 1/2, cos C =1/2, tan B = 1

(2) Sin B =12/13, Cos C= 12/13 ,tag B = 12/5

(3) sin B =21/29, cos C =21/29 ,tag B =21/20

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