Question

In triangle ABC, angleB=90, AC + BC = 25 & AB=5, determine the value of
sin A, Cos A and tan A.​

Answer 1

Answer:

Step-by-step explanation:

AB=5

using pythagoras theorem,

ac^2-BC^2=AB^2        

(AC+BC)(AC-BC)=25

25(AC-BC)=25            

AC-BC=1                        (2)

AC-BC+AC+BC=25+1

2AC=26

AC=13

BC=25-AC

BC=12

sinA=5/13

cos A=12/13

TAN A=5/12

Answer 2

Step-by-step explanation:

$ac {}^{2} = {ab}^{2} + bc {}^{2}$

$ac = 25 - bc$

$(25 - bc) {}^{2} = 25 + bc {}^{2}$

$625 - 50bc + bc {}^{2} = 25 + bc {}^{2}$

$= 600 = 50bc$

$bc = 12$

So the AC = 25-12= 13

Sin A = 5/12.